asd

E tare problema...nu ma vad rezolvand-o!..

Andrei023

9-le poate fi doar in C, D sau F. Mai departe sunt vreo 6 cazuri de verificat. Mi-e somn acum, mai incerc maine :)

ixirimdi

INDICATIe:
careul magic 3x3 SATURN , in care pe orice linie, coloana, diagonala
suma este aceeiasi;
4 9 2
3 5 7
8 1 6

Parmalat

Dupa parerea mea se rezolva incepand cu triunghiul BGI; si cu linia din interiorul lui; RFH; poate daca se va prelungi termenul voi incerca rezolvarea dupa ce voi veni; oricum o voi incerca sa vad daca iese.o zi buna tuturor

Andrei023

A=1; B=4; C=9; D=8; E=3; F=6; G=2; H=5; I=7

dnlac

doua solutii:

a:1
b:4
c:9
d:8
e:3
f:6
g:2
h:5
i:7


a:9
b:6
c:1
d:2
e:7
f:4
g:8
h:5
i:3

dnlac

ca sa vedeti ca nu am copiat o solutie de colo si una de colo:

for (int a = 1; a < 10; a++)
            for (int b = 1; b < 10; b++)
                for (int c = 1; c < 10; c++)
                    for (int d = 1; d < 10; d++)
                        for (int e = 1; e < 10; e++)
                            for (int f = 1; f < 10; f++)
                                for (int g = 1; g < 10; g++)
                                    for (int h = 1; h < 10; h++)
                                        for (int i = 1; i < 10; i++)
                                            if (a+b+c == a+d+h && a+b+c == a+f+i && a+b+c == b+d+g && a+b+c == b+e+i
                                                     && a+b+c == c+e+g && a+b+c == e+f+h && a+b+c == g+h+i
                                                     && a!=b && a!=c && a!=d && a!=e && a!=f && a!=g && a!=h && a!=i
                                                     && b!=c && b!=d && b!=e && b!=f && b!=g && b!=h && b!=i
                                                     && c!=d && c!=e && c!=f && c!=g && c!=h && c!=i
                                                     && d!=e && d!=f && d!=g && d!=h && d!=i
                                                     && e!=f && e!=g && e!=h && e!=i
                                                     &&f!=g && f!=h && f!=i
                                                     && g!=h && g!=i
                                                     && h!= i
                                                     ) {
                                                System.out.println("a:" + a + " ");
                                                System.out.println("b:" + b + " ");
                                                System.out.println("c:" + c + " ");
                                                System.out.println("d:" + d + " ");
                                                System.out.println("e:" + e + " ");
                                                System.out.println("f:" + f + " ");
                                                System.out.println("g:" + g + " ");
                                                System.out.println("h:" + h + " ");
                                                System.out.println("i:" + i + " ");
                                            }                                    
    }