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Friday, 28 june 2013 |
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O problema aparent simpla |
Proposed by
gabibm |
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| (7 comments) | 3.817 times displayed |
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având suma 1-1+1-1+1-1+... (de n ori, n tinde la infinit), care e rezultatul acestei operații? Știți toate rezultatele posibile? |
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Răspuns 1:
(1-1)+(1-1)+(1-1)... = 0
Răspuns 2:
1+(-1+1)+(-1+1)+(-1+1)... = 1
Răspuns 3:
Fie S = 1-1+1-1+1-1+...
1-S = 1 - ( 1-1+1-1+1-1+...) = 1-1+1-1+1-1... = S => S = 1/2
deci care credeți ca e varianta buna?
mai multe detalii vedeți aici: http://www.youtube.com/watch?v=PCu_BNNI5x4 |
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Tags:
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O,
problema,
aparent,
simpla
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