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Tuesday, 16 february 2010 |
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O tabla de sah mai... maricica... |
Proposed by
ily96 |
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| (5 comments) | 5.969 times displayed |
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Pe o tabla de sah 2009*2009 sunt asezati 20092 pioni, cate unul in fiecare casuta.
Fiecare pion se muta intr-o casuta, care are o latura comuna cu casuta lui.
Sa se arate ca ramane o casuta libera. |
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2009=impar. Rezulta 2009*2009=impar => numarul de casute albe nu este egal cu nr de casute negre si presupunem nr casute albe>nr casute negre. Este evident ca pionii de pe casute albe se vor muta in casute negre si invers. Cum nr casute albe> nr casute negre pionii de pe casute albe se vor muta pe un nr mai mic de casute negre=> cel putin doi pioni vor fi in aceeasi casuta => o casuta va fi libera. |
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