|  | 
		                    
			                    | (4 comments) | 6.944 times displayed | 
		                    |  | 
		                    
			                    | Care este al 2011-lea termen in sirul: 1,2,4,7,11,16,....? | 
		                    
			                    | 
 | 
                            |  | 
                            
				                | t1=1t2=t1+1
 t3=t2+2
 .....
 .....
 t2011=t2010+2010
 Adunand relatiile obtinem:
 t1+t2+....t2010+t2011=t1+t2+....+t2010+1+1+2+....+2010 ,de unde prin reducere avem: t2011=1+2010*2011/2=1+1005*2011.
 |